英文原文
Given a string s
and an integer array indices
of the same length.
The string s
will be shuffled such that the character at the ith
position moves to indices[i]
in the shuffled string.
Return the shuffled string.
Example 1:
Input: s = "codeleet", indices
= [4,5,6,7,0,2,1,3]
Output: "leetcode"
Explanation: As shown, "codeleet" becomes "leetcode" after shuffling.
Example 2:
Input: s = "abc", indices
= [0,1,2]
Output: "abc"
Explanation: After shuffling, each character remains in its position.
Example 3:
Input: s = "aiohn", indices
= [3,1,4,2,0]
Output: "nihao"
Example 4:
Input: s = "aaiougrt", indices
= [4,0,2,6,7,3,1,5]
Output: "arigatou"
Example 5:
Input: s = "art", indices
= [1,0,2]
Output: "rat"
Constraints:
s.length == indices.length == n
1 <= n <= 100
s
contains only lower-case English letters.0 <= indices[i] < n
- All values of
indices
are unique (i.e.indices
is a permutation of the integers from0
ton - 1
).
中文题目
给你一个字符串 s
和一个 长度相同 的整数数组 indices
。
请你重新排列字符串 s
,其中第 i
个字符需要移动到 indices[i]
指示的位置。
返回重新排列后的字符串。
示例 1:
输入:s = "codeleet", indices
= [4,5,6,7,0,2,1,3]
输出:"leetcode"
解释:如图所示,"codeleet" 重新排列后变为 "leetcode" 。
示例 2:
输入:s = "abc", indices
= [0,1,2]
输出:"abc"
解释:重新排列后,每个字符都还留在原来的位置上。
示例 3:
输入:s = "aiohn", indices
= [3,1,4,2,0]
输出:"nihao"
示例 4:
输入:s = "aaiougrt", indices
= [4,0,2,6,7,3,1,5]
输出:"arigatou"
示例 5:
输入:s = "art", indices
= [1,0,2]
输出:"rat"
提示:
s.length == indices.length == n
1 <= n <= 100
s
仅包含小写英文字母。0 <= indices[i] < n
indices
的所有的值都是唯一的(也就是说,indices
是整数0
到n - 1
形成的一组排列)。
通过代码
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解题思路
此处撰写解题思路
代码
class Solution {
public String restoreString(String s, int[] indices) {
TreeMap<Integer,String> map=new TreeMap<>();
for(int i=0;i<indices.length;i++){
map.put(indices[i],s.charAt(i)+"");
}
StringBuffer stringBuffer=new StringBuffer();
for(int i:map.keySet()){
stringBuffer.append(map.get(i));
}
return new String(stringBuffer);
}
}
统计信息
通过次数 | 提交次数 | AC比率 |
---|---|---|
30854 | 39301 | 78.5% |
提交历史
提交时间 | 提交结果 | 执行时间 | 内存消耗 | 语言 |
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