原文链接: https://leetcode-cn.com/problems/number-of-valid-words-in-a-sentence
英文原文
A sentence consists of lowercase letters ('a' to 'z'), digits ('0' to '9'), hyphens ('-'), punctuation marks ('!', '.', and ','), and spaces (' ') only. Each sentence can be broken down into one or more tokens separated by one or more spaces ' '.
A token is a valid word if all three of the following are true:
- It only contains lowercase letters, hyphens, and/or punctuation (no digits).
- There is at most one hyphen
'-'. If present, it must be surrounded by lowercase characters ("a-b"is valid, but"-ab"and"ab-"are not valid). - There is at most one punctuation mark. If present, it must be at the end of the token (
"ab,","cd!", and"."are valid, but"a!b"and"c.,"are not valid).
Examples of valid words include "a-b.", "afad", "ba-c", "a!", and "!".
Given a string sentence, return the number of valid words in sentence.
Example 1:
Input: sentence = "cat and dog" Output: 3 Explanation: The valid words in the sentence are "cat", "and", and "dog".
Example 2:
Input: sentence = "!this 1-s b8d!" Output: 0 Explanation: There are no valid words in the sentence. "!this" is invalid because it starts with a punctuation mark. "1-s" and "b8d" are invalid because they contain digits.
Example 3:
Input: sentence = "alice and bob are playing stone-game10" Output: 5 Explanation: The valid words in the sentence are "alice", "and", "bob", "are", and "playing". "stone-game10" is invalid because it contains digits.
Example 4:
Input: sentence = "he bought 2 pencils, 3 erasers, and 1 pencil-sharpener." Output: 6 Explanation: The valid words in the sentence are "he", "bought", "pencils,", "erasers,", "and", and "pencil-sharpener.".
Constraints:
1 <= sentence.length <= 1000sentenceonly contains lowercase English letters, digits,' ','-','!','.', and','.- There will be at least
1token.
中文题目
句子仅由小写字母('a' 到 'z')、数字('0' 到 '9')、连字符('-')、标点符号('!'、'.' 和 ',')以及空格(' ')组成。每个句子可以根据空格分解成 一个或者多个 token ,这些 token 之间由一个或者多个空格 ' ' 分隔。
如果一个 token 同时满足下述条件,则认为这个 token 是一个有效单词:
- 仅由小写字母、连字符和/或标点(不含数字)。
- 至多一个 连字符
'-'。如果存在,连字符两侧应当都存在小写字母("a-b"是一个有效单词,但"-ab"和"ab-"不是有效单词)。 - 至多一个 标点符号。如果存在,标点符号应当位于 token 的 末尾 。
这里给出几个有效单词的例子:"a-b."、"afad"、"ba-c"、"a!" 和 "!" 。
给你一个字符串 sentence ,请你找出并返回 sentence 中 有效单词的数目 。
示例 1:
输入:sentence = "cat and dog" 输出:3 解释:句子中的有效单词是 "cat"、"and" 和 "dog"
示例 2:
输入:sentence = "!this 1-s b8d!" 输出:0 解释:句子中没有有效单词 "!this" 不是有效单词,因为它以一个标点开头 "1-s" 和 "b8d" 也不是有效单词,因为它们都包含数字
示例 3:
输入:sentence = "alice and bob are playing stone-game10" 输出:5 解释:句子中的有效单词是 "alice"、"and"、"bob"、"are" 和 "playing" "stone-game10" 不是有效单词,因为它含有数字
示例 4:
输入:sentence = "he bought 2 pencils, 3 erasers, and 1 pencil-sharpener." 输出:6 解释:句子中的有效单词是 "he"、"bought"、"pencils,"、"erasers,"、"and" 和 "pencil-sharpener."
提示:
1 <= sentence.length <= 1000sentence由小写英文字母、数字(0-9)、以及字符(' '、'-'、'!'、'.'和',')组成- 句子中至少有
1个 token
通过代码
高赞题解
class Solution {
public:
//判断函数
bool jg(string s){
int k=0;
if(s.size()==0){return false;} //可以很好的处理多个空格问题
for(auto t:s){ //先判断数字,这样条理更清晰
if(isdigit(t)){return false;}//isdigit()函数判断字符串是否全为数字
}
for(int i=0;i<s.size();i++){
if(s[i]==','||s[i]=='.'||s[i]=='!'){//再判断标点
if(i!=s.size()-1){return false;}
}
if(s[i]=='-'){ //最后判断-,到此已经不会再有数字或者别的符号了
if(k++){return false;} //判断是否只有有一个'-'
if(i==0||i==s.size()-1||!isalpha(s[i+1])){return false;}
}
}
return true;
}
int countValidWords(string sentence) {
string t=""; //用于存放每个小串
int sum=0;
for(int i=0;i<sentence.size();i++){//简单实现字符串分割
if(sentence[i]==' '){
if(jg(t)){sum++;}
t=""; //不要忘记每次遇到空格t都要清空
continue;
}
t+=sentence[i];
}
if(jg(t)){sum++;} //最后一个小串的后面可能没有空格,要单独判断
return sum;
}
};
统计信息
| 通过次数 | 提交次数 | AC比率 |
|---|---|---|
| 4785 | 16809 | 28.5% |
提交历史
| 提交时间 | 提交结果 | 执行时间 | 内存消耗 | 语言 |
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